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CBSE Syllabus 2021-22 for 9th, 10th, 11th, 12th Released: Applicable for CBSE Academic Session 2021-22
Subject-wise New CBSE Syllabus 2021-22 (PDF) for 9th, 10th, 11th & 12th has been officially released online at cbseacademic.nic.in. The new CBSE Syllabus is applicable for CBSE Academic Session 2021-22. The board has already instructed CBSE Schools to start new CBSE Academic Session 2021-22 from April and the board has released the new syllabus before April 2021.
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CBSE Class 10 New Syllabus for Academic Session 2021-2022 Released.
We are providing here the CBSE Class 10 Syllabus 2021-22. Students of class 10 can download from here the new syllabus of all subjects to know the course structure and assessment scheme for the new academic year and plan their studies accordingly.
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CBSE Class 10 New Syllabus for Academic Session 2021-2022 Released.
We are providing here the CBSE Class 10 Syllabus 2021-22. Students of class 10 can download from here the new syllabus of all subjects to know the course structure and assessment scheme for the new academic year and plan their studies accordingly.
RD sharma class 10 chapter 1 Real Numbers
RD Sharma Solutions For Class 10 Math Chapter 1 Real Numbers Exercise 1.1
Q1. If a and b are two odd positive integers such that a > b, then prove that one of the two numbers \(\frac{a+b}{2} \) and \(\frac{a-b}{2} \) is odd and the other is even.
Solution: We know that any odd positive integer is of the form 4q+1 or, 4q+3 for some whole number q. Now that it’s given a > b
So, we can choose a= 4q+3 and b= 4q+1.
∴ \( \frac{a+b}{2}=\frac{\left[ (4q+3)+(4q+1) \right]}{2} \)
⇒ \(\Rightarrow \frac{a+b}{2}=\frac{8q+4}{2} \)(a+b)/2 = (8q+4)/2 ⇒ (a+b)/2 = 4q+2 = 2(2q+1) which is clearly an even number.
Now, doing (a-b)/2
⇒ \(\Rightarrow \frac{a-b}{2}=\frac{\left[ (4q+3)-(4q+1) \right]}{2} \)
⇒ (a-b)/2 = (4q+3-4q-1)/2
⇒ (a-b)/2 = (2)/2
⇒ (a-b)/2 = 1 which is an odd number.
Hence, one of the two numbers (a+b)/2 and (a-b)/2 is odd and the other is even.
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