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CBSE Syllabus 2021-22 for 9th, 10th, 11th, 12th Released: Applicable for CBSE Academic Session 2021-22
Subject-wise New CBSE Syllabus 2021-22 (PDF) for 9th, 10th, 11th & 12th has been officially released online at cbseacademic.nic.in. The new CBSE Syllabus is applicable for CBSE Academic Session 2021-22. The board has already instructed CBSE Schools to start new CBSE Academic Session 2021-22 from April and the board has released the new syllabus before April 2021.
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CBSE Class 10 New Syllabus for Academic Session 2021-2022 Released.
We are providing here the CBSE Class 10 Syllabus 2021-22. Students of class 10 can download from here the new syllabus of all subjects to know the course structure and assessment scheme for the new academic year and plan their studies accordingly.
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CBSE Class 10 New Syllabus for Academic Session 2021-2022 Released.
We are providing here the CBSE Class 10 Syllabus 2021-22. Students of class 10 can download from here the new syllabus of all subjects to know the course structure and assessment scheme for the new academic year and plan their studies accordingly.
RD sharma class 10 Chapter 13 Coordinate Geometry
Class 9 Chapter 3 (Coordinate Geometry) Class Notes
Coordinate Geometry
Cartesian System
If we take two number lines, one horizontal and one vertical, and then combine them in such a way that they intersect each other at their zeroes, and then they form a Cartesian Plane.

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The horizontal line is known as the x-axis and the vertical line is known as the y-axis.
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The point where these two lines intersects each other is called the origin. It is represented as ‘O’.
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OX and OY are the positive directions as the positive numbers lie in the right and upward direction.
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Similarly, the left and the downward directions are the negative directions as all the negative numbers lie there.
Quadrants of the Cartesian Plane
The Cartesian plane is dividing into four quadrants named as Quadrant I, II, III, and IV anticlockwise from OX.

Coordinates of a Point
To write the coordinates of a point we need to follow these rules-
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The x - coordinate of a point is marked by drawing perpendicular from the y-axis measured a length of the x-axis .It is also called the Abscissa.
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The y - coordinate of a point is marked by drawing a perpendicular from the x-axis measured a length of the y-axis .It is also called the Ordinate.
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While writing the coordinates of a point in the coordinate plane, the x - coordinate comes first, and then the y - coordinate. We write the coordinates in brackets.

In the above figure, OB = CA = x coordinate (Abscissa), and CO = AB = y coordinate (Ordinate).
We write the coordinate as (x, y).
Remark: As the origin O has zero distance from the x-axis and the y-axis so its abscissa and ordinate are zero. Hence the coordinate of the origin is (0, 0).
The relationship between the signs of the coordinates of a point and the quadrant of a point in which it lies.

| Quadrant | Coordinate | Sign in the quadrant |
| I | (+, +) | 1st quadrant is enclosed by the positive x-axis and the positive y-axis. |
| II | (-, +) | 2nd quadrant is enclosed by the negative x-axis and the positive y-axis. |
| III | (-, -) | 3rd quadrant is enclosed by the negative x-axis and the negative y-axis. |
| IV | (+, -) | 4th quadrant is enclosed by the positive x-axis and the negative y-axis |
Plotting a Point in the Plane if its Coordinates are Given

Steps to plot the point (2, 3) on the Cartesian plane -
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First of all, we need to draw the Cartesian plane by drawing the coordinate axes with 1 unit = 1 cm.
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To mark the x coordinates, starting from 0 moves towards the positive x-axis and count to 2.
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To mark the y coordinate, starting from 2 moves upwards in the positive direction and count to 3.
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Now this point is the coordinate (2, 3)
Likewise, we can plot all the other points, like (-3, 1) and (-1.5,-2.5) in the right site figure.
Is the coordinates (x, y) = (y, x)?
Let x = (-4) and y = (-2)
So (x, y) = (- 4, – 2)
(y, x) = (- 2, - 4)
Let’s mark these coordinates on the Cartesian plane.

You can see that the positions of both the points are different in the Cartesian plane. So,
If x ≠ y, then (x, y) ≠ (y, x), and (x, y) = (y, x), if x = y.

Example: Write the coordinates of the points marked on the axes.From the figure,
(i) The coordinates of point A are (4, 0).
(ii) The coordinates of point B are (0, 3).
(iii) The coordinates of point C are (-5, 0).
(iv) The coordinates of point D are (0, -4).
(v) The coordinates of point E are (2/3, 0).
Example:
Plot the points (6, 4), (- 6,- 4), (- 6, 4) and (6,- 4) on the Cartesian plane.
Solution:
As you can see in (6, 4) both the numbers are positive so it will come in the first quadrant.
For x coordinate, we will move towards the right and count to 6.
Then from that point go upward and count to 4.
Mark that point as the coordinate (6, 4).

Similarly, we can plot all the other three points.
Class 10 Chapter 7 (Coordinate Geometry) Class Notes
Revision Notes on Coordinate Geometry
Cartesian Coordinate System
In the Cartesian coordinate system, there is a Cartesian plane which is made up of two number lines which are perpendicular to each other, i.e. x-axis (horizontal) and y-axis (vertical) which represents the two variables. These two perpendicular lines are called the coordinate axis.
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The intersection point of these two lines is known as the center or the origin of the coordinate plane. Its coordinates are (0, 0).
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Any point on this coordinate plane is represented by the ordered pair of numbers. Let (a, b) is an ordered pair then a is the x-coordinate and b is the y-coordinate.
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The distance of any point from the y-axis is called its x-coordinate or abscissa and the distance of any point from the x-axis is called its y-coordinate or ordinate.
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The Cartesian plane is divided into four quadrants I, II, III and IV.
Distance formula
The distance between any two points A(x1,y1) and B(x2,y2) is calculated by


Example
Find the distance between the points D and E, in the given figure.

Solution

This shows that this is same as Pythagoras theorem. As in Pythagoras theorem

Distance from Origin
If we have to find the distance of any point from the origin then, one point is P(x,y) and the other point is the origin itself, which is O(0,0). So according to the above distance formula, it will be

Section formula
If P(x, y) is any point on the line segment AB, which divides AB in the ratio of m: n, then the coordinates of the point P(x, y) will be


Mid-point formula
If P(x, y) is the mid-point of the line segment AB, which divides AB in the ratio of 1:1, then the coordinates of the point P(x, y) will be

Area of a Triangle

Here ABC is a triangle with vertices A(x1, y1), B(x2, y2) and C(x3, y3). To find the area of the triangle we need to draw AP, BQ and CR perpendiculars from A, B and C, respectively, to the x-axis. Now we can see that ABQP, APRC and BQRC are all trapeziums.
Area of triangle ABC = Area of trapezium ABQP + Area of trapezium APRC – Area of trapezium BQRC.

Therefore,

Remark: If the area of the triangle is zero then the given three points must be collinear.
Example
Let’s see how to find the area of quadrilateral ABCD whose vertices are A (-4,-2), B (-3,-5), C (3,-2) and D (2, 3).
If ABCD is a quadrilateral then we get the two triangles by joining A and C. To find the area of Quadrilateral ABCD we can find the area of ∆ ABC and ∆ ADC and then add them.




Area of a Polygon
Like the triangle, we can easily find the area of any polygon if we know the coordinates of all the vertices of the polygon.
If we have a polygon with n number of vertices, then the formula for the area will be


Where x1 is the x coordinate of vertex 1 and yn is the y coordinate of the nth vertex etc.
Example
Find the area of the given quadrilateral.

Solution
To find the area of the given quadrilateral-
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Make a table of x and y coordinates of each vertex. Do it clockwise or anti-clockwise.

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Simplify the first two rows by:
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Multiplying the first row x by the second row y. (red)
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Multiplying the first row y by the second row x (blue)
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Subtract the second product form the first.
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Repeat this for all the other rows.
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Now add these results.

The area of the quadrilateral is 45.5 as area will always be in positive.
Centroid of a Triangle
Centroid of a triangle is the point where all the three medians of the triangle meet with each other.

Here ABC is a triangle with vertices A(x1, y1), B(x2, y2) and C(x3, y3). The centroid of the triangle is the point with the coordinates (x, y).
The coordinates of the centroid will be calculated as

Remarks
In coordinate geometry, polygons are formed by x and y coordinates of its vertices. So in order to prove that the given figure is a:
| No. | Figures made of four points | Prove |
| 1. | Square | Its four sides are equal and the diagonals are also equal. |
| 2. | Rhombus | Its four sides are equal. |
| 3. | Rhombus but not square | Four sides are equal and the diagonals are not equal. |
| 4. | Rectangle | Its opposite sides are equal and the diagonals are equal. |
| 5. | Parallelogram | Its opposite sides are equal. |
| 6. | Parallelogram but not a rectangle | Its opposite sides are equal but the diagonals are not equal. |
| No. | Figures made of three points | Prove |
| 1. | A scalene triangle | If none of its sides are equal. |
| 2. | An Isosceles triangle | If any two sides are equal. |
| 3. | Equilateral triangle | If it’s all the three sides are equal. |
| 4. | Right triangle | If the sum of the squares of any two sides is equal to the square of the third side. |
Example
If the coordinates of the centroid of a triangle are (1, 3) and two of its vertices are (- 7, 6) and (8, 5), then what will be the third vertex of the triangle?
Solution
Let the third vertex of the triangle be P(x, y)
Since the centroid of the triangle is (1, 3)
Therefore,

Hence the coordinate of the third vertex are (2, – 2).
cbse class 10th coordinate geometry